1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Velocity to Distance (graph)

  1. Nov 8, 2012 #1
    1. The problem statement, all variables and given/known data
    A velocity of a runner is described in the graph below. The runner started from X=0 on the X axis. In what distance from X=0 (beggining) will be the runner, after 11.5 sec.


    2. Relevant equations

    3. The attempt at a solution

    Please tell me why it isnt 42m.:confused:
  2. jcsd
  3. Nov 8, 2012 #2
    V=m*s, so that means the area of the graph gives us the distance from X=0. then;

    32(the 2*1 areas)+ 4 (the first triangle) + 2 (the second triangle) (from X=0 to 10. sec)

    now calculate the +1,5 sec area which is 1,5*4=6

    then 38+6=44, right?
    Last edited: Nov 8, 2012
  4. Nov 8, 2012 #3
    Thanks goktr001, but i have just solved it, its actually 44.
    I summed the area under the graph, but only till the 11sec, i didnt notice that 11.5 is actually 3 quarders of triangle.

    Problem solved anyway. thanks.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook