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Velocity vs displcement graph

  1. Jun 21, 2013 #1
    1. The problem statement, all variables and given/known data
    The graph is as folllows-(SEE ATTACHMENT)
    Q.draw acceleration vs disp. graph.

    2. Relevant equations
    Basic equations of motion, basic calculus

    3. The attempt at a solution
    I have tried to write a linear equation in v and s and then differentiating it w.r.t. to time. but im not sure if this is the correct way to do it. It gives me a positive slope and -ve y intercept.
    Also if there is/are any other ways please do tell
     

    Attached Files:

  2. jcsd
  3. Jun 21, 2013 #2
    first write the v-s equation, but do not diffrentiate it with time(as it would add one more variable which is not needed)

    Hint: What is the relation between v,a and s?
     
  4. Jun 21, 2013 #3
    thanks for your reply.
    i have solved the question.
    1 doubt though which extra variable is generated? on differentiation
    v becomes a
    s becomes v
    constant is eliminated
     
  5. Jun 21, 2013 #4
    I thought 't" would create some some problems but thanks it is eliminated. You can also do it using the relation a = v*dv/ds. This was what i was refering to!
     
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