A. Q: FIND THE maximum velocity. During what time interval does this velocity occur? A: The maximum velocity is 16 m/s, and it occurs between 35 and 50 seconds. Am I right? b. Q: The velocity is negative from 30 t0 35 s. What does this mean? A: I think this means that the car is backing up, and goes past it's reference point, from where it started. c. Q: Find the displacement during the following time intervals: A: 0s to 14s = v=d/t so d= vt = (9m/s)(14s) = 126 m 14s to 30s = d=vt = (0m/s)(16s) = 0m 30s to 35s = d =vt = (-4m/s)(5s) = -20m 35 to 50s = d=vt = (16 m/s)(15s) = 240m d. Q: What is the total displacement? A: 126m+0m+(-20m)+240m = 346m e. Q: What is the average velocity? A: 9m/s + 0m/s + -4m/s + 16 m/s = 21 m/s / 4 = 5.25 m/s Is this the right way to find the average velocity? Or should I find it with another method?