Calculating Pressure Difference Between Sections 1 and 2

In summary, The conversation is about calculating the pressure difference between sections 1 and 2, with the given values of 32mm and 20mm. The formula for this is P1-P2 = 1/2 density x (vi^2 - vj^2). The next question is about finding the head loss, with an example of 45mm. The relation between static pressure difference and fluid column height is P2-P1 = density x g x h1-h2. The formula for this is h1-h2 = p2-p1 / density x g.
  • #1
timothy1875
9
0
Trying to calculate pressure difference between sections 1 and 2.
1=32mm 2=20mm
density = 1000 kg/m^3

I have done P1-P2 = 1/2 density x (vi^2 - vj^2)

Is this right?

How do I now find head loss if difference between 1 and 2 were 45mm ?

45/density x gravity ?

Thanks,
 
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  • #2
Your equation for P1 - P2 looks OK (in the absence of friction and assuming the discharge coefficient = 1).

The relation between static pressure difference and fluid column height ("head loss") is:

P2 - P1 = density X g X h1 - h2. Is your head loss 45 mm or was that just an example?
 
  • #3
Ye 45mm is the head loss but it's theoretical and not related to the initial equation. Would the formula be h1 - h2 = p2 - p1 / density x g ?

Thanks for your help
 
  • #4
timothy1875 said:
Ye 45mm is the head loss but it's theoretical and not related to the initial equation. Would the formula be h1 - h2 = p2 - p1 / density x g ?

Thanks for your help
Yes.
 
  • #5


I would like to commend you for taking the initiative to calculate the pressure difference between sections 1 and 2. Your formula for calculating pressure difference (P1-P2 = 1/2 density x (vi^2 - vj^2)) is correct. However, I would suggest using the units of meters for consistency, so the formula would be P1-P2 = 1/2 density x (vi^2 - vj^2) in m^2/s^2. This will ensure that your final answer is in units of pressure (Pascal or Pa).

To find the head loss, you can use the formula H = (P1-P2)/(density x gravity), where H is the head loss in meters, P1-P2 is the pressure difference in Pa, density is in kg/m^3, and gravity is in m/s^2. So for your example, the head loss would be (45/1000 x 9.8) = 0.441 m.

It is important to note that this formula assumes a constant density and does not take into account any other factors that may affect the pressure, such as friction or changes in velocity. Therefore, it is always best to perform experiments or simulations to confirm your calculations and consider any other factors that may affect the pressure difference. I hope this helps and good luck with your calculations!
 

1. How do you calculate the pressure difference between two sections?

To calculate the pressure difference between two sections, you need to know the pressure at each section and the distance between them. Then, you can use the formula: ΔP = P2 - P1, where ΔP is the pressure difference, P2 is the pressure at section 2, and P1 is the pressure at section 1. This will give you the pressure difference in units of pressure, such as Pascals or pounds per square inch (psi).

2. What is the significance of calculating pressure difference between two sections?

Calculating pressure difference between two sections allows us to understand the change in pressure within a system. This can provide valuable information about the behavior of fluids or gases, and can help us predict how they will move or interact with their surroundings. It is an important concept in many fields of science and engineering, including fluid mechanics, meteorology, and aerodynamics.

3. Can pressure difference between two sections be negative?

Yes, pressure difference between two sections can be negative. This can occur when the pressure at section 2 is less than the pressure at section 1. In this case, the pressure difference would be a negative value, indicating a decrease in pressure from section 1 to section 2.

4. How is pressure difference affected by temperature?

The pressure difference between two sections is affected by temperature through the ideal gas law, which states that pressure and temperature are directly proportional for a fixed volume of gas. This means that as temperature increases, the pressure will also increase, and vice versa. Therefore, an increase in temperature can result in a larger pressure difference between two sections.

5. Are there any assumptions made when calculating pressure difference between two sections?

When calculating pressure difference between two sections, it is assumed that the fluid or gas is incompressible, meaning that its density remains constant. This is often a reasonable assumption for liquids and gases at low speeds and pressures. Additionally, it is assumed that the pressure at each section is uniform and there are no external forces acting on the system.

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