Verification of a parabola

1. Aug 25, 2005

TonyC

x^2-2xy+y^2+5x+5y=0

using the formulas b^2-4ac=0 (indicates a parabola)
b^2-4ac<0 (indicates an ellipse)
b^2-4ac>0 (indicates a hyperbola)

2^2-4(1)(1)=0
4-4=0 therefore this graph must be a parabola!

Am I correct?

2. Aug 25, 2005

TD

It's indeed a parabola

3. Aug 25, 2005

TonyC

YIPPEE, thank

4. Aug 25, 2005

arildno

Note that your equation may be re-written as:
$$(x-y)^{2}+5(x+y)=0$$
This can be brought onto the form:
$$u=-\frac{\sqrt{2}}{5}v^{2}, u=\frac{x+y}{\sqrt{2}}, v=\frac{x-y}{\sqrt{2}}$$
where the u-v axes are 45 degrees rotated with respect to the xy axes.