- #1

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## Homework Statement

I want to verify

[tex]j^{-p}=e^{-j\frac{p\pi}{2}}[/tex]

## Homework Equations

[tex]e^{j\frac{\pi}{2}}=\cos(\frac{\pi}{2})+j\sin(\frac{\pi}{2})=j[/tex]

## The Attempt at a Solution

[tex]j^{-p}=(e^{j\frac{\pi}{2}})^{-p}=e^{-j\frac{p\pi}{2}}[/tex]

Am I correct?

Thanks