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Verilog error message 10159

  1. May 1, 2013 #1
    I'm currently working on a project to create a binary calculator using verilog, which I will eventually program onto a DE2 FPGA board. Im trying to wrte my code but I keep getting the following error message.
    "Error (10159): Verilog HDL error at calculator.v(37): "Display" is not a task or void function"

    I have never seen this before. The following is part of my code where this happens

    Code (Text):

    always @(*)begin

    if(KEY[0] == 0 && KEY[0] != 1) //if addittion button
        result = SW[15:8] + SW[7:0];  //addition for the 2 numbers    

        Display (SW[15:8], HEX6);  <--- error occurs here
    this is my module that I'm calling

    Code (Text):

    module Display(num, hex);

    input [7:0] num; //8-bit input
        output reg [6:0] hex; //7-segment display
        always@(num) begin

                0: hex =  7'b1000000;
                1: hex =  7'b1111001;
                2: hex =  7'b0100100;
                3: hex =  7'b0110000;
                4: hex =  7'b0011001;
                5: hex =  7'b0010010;
                6: hex =  7'b0000010;
                7: hex =  7'b1111000;
                8: hex =  7'b0000000;
                9: hex =  7'b0010000;
                10: hex = 7'b0001000;
                11: hex = 7'b0000011; //B
               12: hex = 7'b1000110; //C
               13: hex = 7'b0100001; //D
                14: hex = 7'b0000110; //E
                15: hex = 7'b0001110; //F
                    default: hex = 7'b1000000;

    I'm not sure if this is the right forum to post this queston but any advice would be appreciated.
  2. jcsd
  3. May 2, 2013 #2
    You are getting the error because you are not instantiating the module "Display" correctly in your top level. It should be:
    Display Name_of_this_Particular_Instance_of_the_Module_Display (SW[15:8], HEX6);


    Display Display_Instance1 (SW[15:8], HEX6);

    Why are you passing SW[15:8] to the display and not the result of the addition?
  4. May 2, 2013 #3
    I'm passing one of the inputs because I need to display both the input and output. That's just a piece of the ode like I said. I took the call out of the "always @" and it solved the problem. Thank you for the reply.
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