# Vertical force

## Homework Statement

A truck (mass 12000 kg) carries a load of 16000kg. What vertical force is exerted on the road by each wheel assuming the mass is uniformly spread?

F=ma[/B]

## The Attempt at a Solution

12000kg+16000kg=28000kg total mass
28000/4=7000kg to get mass on each wheel[/B]
F=ma 7000kgx9.81=68670 N

Last edited:

gneill
Mentor

## Homework Statement

A truck (mass 1.2 x 104 kg) carries a load of 1.6 x 104 kg. What vertical force is exerted on the road by each wheel assuming the mass is uniformly spread?

F=ma[/B]

## The Attempt at a Solution

1.2 x 104 kg+1.6 x 104 kg=291.2kg total mass
291.2/4=72.8kg to get mass on each wheel[/B]
F=ma 72.8kgx9.81=714 N
Those numbers in the problem statement are given using scientific notation, although the powers of ten are missing the superscript for the exponents. So for the truck mass, for example, 1.2 x 104 kg should read: 1.2 x 104 kg, which is equivalent to 12000 kg.

Those numbers in the problem statement are given using scientific notation, although the powers of ten are missing the superscript for the exponents. So for the truck mass, for example, 1.2 x 104 kg should read: 1.2 x 104 kg, which is equivalent to 12000 kg.

I have made the changes is the method i used correct though?

I have another question and I have no clue on how to attempt this one

The lorry starts from rest with an acceleration of 2 ms-2.
What is the effective thrust is being exerted?

gneill
Mentor
I have made the changes is the method i used correct though?
The method is okay and will deliver the correct result.

If it were me doing the problem I would probably find the total mass then convert that to total weight (multiply mass by g) before finally dividing by four to find the weight (force) supported by each wheel.

fleur
gneill
Mentor
I have another question and I have no clue on how to attempt this one

The lorry starts from rest with an acceleration of 2 ms-2.
What is the effective thrust is being exerted?