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Vertical launch, projectile Q

  1. Oct 10, 2007 #1
    First, let us consider an object launched vertically upward with an initial speed v. Neglect air resistance. What is the speed of the object at the height of (1/2)h max? i know that h max = (initial v in the y direction / 2g) and i also know that Kinitial +Uinitial =Kfinal +Ufinal or 0.5(mv^2) = 0.25(mv^2) + mg(.5 h max)

    please help! you will be blessed, i swear... :)
  2. jcsd
  3. Oct 10, 2007 #2


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    Homework Helper

    your formula is wrong.

    hmax = (vinitial^2)/(2g)

    now use the equation:

    vf^2 = vi^2 + 2ad

    use d = (1/2)hmax. use a = -g. use vi = vinitial... and that's it. solve for vf.
  4. Oct 10, 2007 #3
    ok i got it. thanks^^
    Last edited: Oct 10, 2007
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