[tex] 16x^2+9y^2+192y-36y+468=0 [/tex](adsbygoogle = window.adsbygoogle || []).push({});

Was the original conic i had to conver this into standard form and got

[tex] \frac {(x+6)^2} {9} + \frac {(y-2)^2} {16} =1 [/tex]

Im not sure if this is a horizontal or vertical ellipse

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# Homework Help: Vertical or Horizontal ellipse?

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