I have a question about vertical oscillations. If a vertical spring, fixed at one end with a mass attached to the other and held so that the spring is not stretched.. is then released, will the amplitude of the subsequent oscillations be the distance between the new equilibrium point (of mass and spring system) and the height at which it was held before it was released? If that makes any sense. For example, in class we've talked about how the force of gravity only plays a role in determining the equilibrium point and does not affect the actual motion. All the problems we've covered have said "the spring is stretched x meters from the equilibrium point"- so you know that's the amplitude. So I'm wondering if you drop a spring from a certain height above its equilibrium point, will that height be the height of the subsequent oscillations?