- #1
Idividebyzero
- 64
- 0
1. A 2.79 kg block is pushed 1.48 m up a vertical
wall with constant speed by a constant force
of magnitude F applied at an angle of 60.8
with the horizontal.
The acceleration of gravity is 9.8 m/s2 .If the coefficient of kinetic friction between
the block and wall is 0.581, find the work done
by F
2W=FD
3. seems pretty straight foward but i guess I am missing something. first attempt was W= (m)(g)(D)
W= (2.79kg)(9.8m/s^2)(cos(90-60.8))(1.48)
W=35.3J
that answer seems reasonable, but is not correct. first question is only asking what the work done by F is disregarding the friction. next question is about the work done by friction.(
wall with constant speed by a constant force
of magnitude F applied at an angle of 60.8
with the horizontal.
The acceleration of gravity is 9.8 m/s2 .If the coefficient of kinetic friction between
the block and wall is 0.581, find the work done
by F
2W=FD
3. seems pretty straight foward but i guess I am missing something. first attempt was W= (m)(g)(D)
W= (2.79kg)(9.8m/s^2)(cos(90-60.8))(1.48)
W=35.3J
that answer seems reasonable, but is not correct. first question is only asking what the work done by F is disregarding the friction. next question is about the work done by friction.(