Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Vertical, spring and frequency

  1. Apr 14, 2008 #1
    1. The problem statement, all variables and given/known data

    A massless spring hangs from the ceiling with a small object attached to its lower end. The object is initially held at rest in a position yi such that the spring is at its rest length. The object is then released from yi and oscillates up and down, with its lowest position being 21 cm below yi.

    What is the frequency of the oscillation?

    2. Relevant equations

    T = 2pi sqrt(m/k)

    Analyzing the forces,

    At the rest position:
    Fnet = k(yi) - mg = o
    k(yi) = mg

    Maximum distance below the rest position,

    Fnet = k([tex]\Delta[/tex]y)

    I know that the total energy of the system is given by the following:

    E= U + K = 1/2k(A)^2

    3. The attempt at a solution

    Since I finding frequency I can just take the reciprocal for the equation for period:
    f = (1/2pi)*sqrt(k/m)

    I don't have any masses given so I'm assuming that I have to find the analytic solution for k that will cancel out the m.

    I know that k = (mg/yi) but I wasn't given what yi is.

    I'm think I have to do something with the energy of the system.

    I really think I need more information, but there must be some way to solve this problem.
  2. jcsd
  3. Apr 14, 2008 #2

    Shooting Star

    User Avatar
    Homework Helper

    The first step is to prove that an oscillating body hanging from a spring executes SHM.

    Let a body of mass m hang in equilibrium by stretching the spring by a length of x1. Then,

    mg = kx1.


    Now suppose the spring is stretched by a dist x2 from its unstretched length position. Write down the force eqn and prove that it is indeed an SHM. (Consider x=x2-x1.)

    After that, you can use all the results of SHM.
    Last edited: Apr 14, 2008
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook