A rope of mass m and length L is suspended vertically. Show that a transverse wave pulse will travel the length of the tope in a time t = 2(L/g)^1/2. stuck... i tried: v = (T/u)^1/2 ; where T = m(X/L)g and u = m/L the X is the distance from the bottom of the string... so i got v= (xg)^1/2 t= (L-X)/ (xg)^1/2 which i can't simplify to t = 2(L/g)^1/2. Where did I go wrong here? logic is making sense to me but im no getting the answer. thanks.