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Vertically Oriented Dipole magnetism

  1. Oct 15, 2011 #1
    Now assume you are taking a profile in the x-direction along y=0. Show that the distance between the zero crossings of Bz for this vertical dipole is equal to 2d√2
    2, and that the distance between maximum and
    minimum values of Bx is equal to d


    2. Relevant equations
    Bx=[μo/(4∏((x2p+y2p+d2)3/2)](-3dxp/(x2p+y2p+d2))
    rp=[xp,yp,0] position of observer
    rq=[0,0,d] vertically downward dipole
    x=xp-xq
    3. The attempt at a solution
    I'm not entirely sure how to go about solving this problem any tips on what to start with would be helpful
     
  2. jcsd
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