# Vertically Oriented Dipole magnetism

1. Oct 15, 2011

### dp182

Now assume you are taking a proﬁle in the x-direction along y=0. Show that the distance between the zero crossings of Bz for this vertical dipole is equal to 2d√2
2, and that the distance between maximum and
minimum values of Bx is equal to d

2. Relevant equations
Bx=[μo/(4∏((x2p+y2p+d2)3/2)](-3dxp/(x2p+y2p+d2))
rp=[xp,yp,0] position of observer
rq=[0,0,d] vertically downward dipole
x=xp-xq
3. The attempt at a solution