Vertically Oriented Dipole magnetism

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Now assume you are taking a profile in the x-direction along y=0. Show that the distance between the zero crossings of Bz for this vertical dipole is equal to 2d√2
2, and that the distance between maximum and
minimum values of Bx is equal to d


Homework Equations


Bx=[μo/(4∏((x2p+y2p+d2)3/2)](-3dxp/(x2p+y2p+d2))
rp=[xp,yp,0] position of observer
rq=[0,0,d] vertically downward dipole
x=xp-xq

The Attempt at a Solution


I'm not entirely sure how to go about solving this problem any tips on what to start with would be helpful
 

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