1. The problem statement, all variables and given/known data Brad tosses a rock straight up at 40.0 m/s. What is the rock's velocity after 1.8 seconds? (answer 22.36 m/s) What is the velocity of the rock from the question above after 5.2 seconds? (answer -10.96) What is the maximum height of the rock from the question above? 2. Relevant equations V=Vo+at X=Xo+Vot+1/2at^2 V^2=Vo^2+2a(X-Xo) 3. The attempt at a solution I tried to find the maximum height for both times, but neither one was the right answer. I did the second equation (X=(40)(1.8)+1/2(-9.8)(3.24) and got 56.124 m and that wasn't right) then I tried the second equation with the second time (X=(40)(5.2)+1/2(-9.8)(27.04) and got the answer to be 75.504), but that wasn't right either. Please tell me what I am doing wrong! *hint: the difference between the squares of the initial and final speeds is equal to twice the product of the acceleration due to gravity and the displacement.