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Very basic water pressure problem

  1. Aug 21, 2015 #1
    1. The problem statement, all variables and given/known data

    Assuming g = 10 ms^-2 and the volumetric mass for water is 10^3 kg.m^-3 and the air pressure is 10^5 Pa, the total pressure on a point inside the water that's in equilibrium with a distance of 2m from its free surface is:

    A. 0.8 * 10^5

    B. 1.002 * 10^5

    C. 1.2 * 10^5

    D. 1.02 * 10^5


    2. Relevant equations


    3. The attempt at a solution

    What I did was apply: Pnet = Pair + ρ*g*h

    Pnet = 10^5 + 10^3 * 10 * 2

    Pnet = 10^5 + 10^4 *2


    What am I doing wrong?
     
  2. jcsd
  3. Aug 21, 2015 #2

    RUber

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    Why do you think you are doing something wrong?
     
  4. Aug 21, 2015 #3
    Oh nevermind, lock this.

    I never bothered to actually calculate how much is 10^5 + 10^4 * 2
     
  5. Aug 21, 2015 #4
    Try writing your answer in proper scientific notation...
     
  6. Aug 21, 2015 #5

    RUber

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    Homework Helper

    :oldsurprised:
     
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