Solving a Difficult Integral: Strategies and Advice

  • Thread starter dirk_mec1
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In summary, MadHawk suggests replacing the denominator with a degree 16 polynomial in order to simplify the problem. Dick and HallsofIvy have not been seen in some time.
  • #1
dirk_mec1
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Homework Statement



[tex]
\int \frac{x}{\sqrt{x^4 + 10 x^2 - 96 x - 71}}\ \mbox{d}x
[/tex]

The Attempt at a Solution


I don't see what's useful completing a square, gonio substitution (or even a useful substitution). Does anyone have an idea?
 
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  • #2
The denominator can be replaced as [{(x^2+5)^2/96 - 1}^2 + 5]^2.

P.S. That /96 is to the whole (x^2+5)^2 expression.
 
  • #3
MadHawk said:
The denominator can be replaced as [{(x^2+5)^2/96 - 1}^2 + 5]^2.

P.S. That /96 is to the whole (x^2+5)^2 expression.
That's a degree 16 polynomial, there MadHawk.

dirk_mec1 said:

Homework Statement



[tex]
\int \frac{x}{\sqrt{x^4 + 10 x^2 - 96 x - 71}}\ \mbox{d}x
[/tex]


The Attempt at a Solution


I don't see what's useful completing a square, gonio substitution (or even a useful substitution). Does anyone have an idea?

Was this a homework problem, Dirk? Could you provide some context as to where it arose. According to the integrator at http://integrals.wolfram.com/index.jsp?expr=x/Sqrt[x^4+10*x^2-96*x-71]&random=false, it would seem the integral as you have written it cannot be expressed in elementary terms.
 
  • #4
MadHawk said:
The denominator can be replaced as [{(x^2+5)^2/96 - 1}^2 + 5]^2.

P.S. That /96 is to the whole (x^2+5)^2 expression.

Your expression isn't even of the same degree as the denominator in the original expression:eek:

I think you'd better double check your math on that one!:wink:
 
  • #5
dirk_mec1 said:

Homework Statement



[tex]
\int \frac{x}{\sqrt{x^4 + 10 x^2 - 96 x - 71}}\ \mbox{d}x
[/tex]


The Attempt at a Solution


I don't see what's useful completing a square, gonio substitution (or even a useful substitution). Does anyone have an idea?

Hmmm... are you sure that [itex]-96x[/itex] is supposed to be there?
 
  • #6
Well, it was just pure innocent fun. The actual quantity under root is (x^2+5)^2 - 96(x+1). From here, I think, it can be done. Sorry folks, for the joke above.
 
  • #7
gabbagabbahey said:
Hmmm... are you sure that [itex]-96x[/itex] is supposed to be there?

Yes, this IS the correct integral. Furthermore there is an exact solution which can be written in elementary functions. What can you advice me to do? Is Madhawks suggestion the way to tackle this integral?

Where are Dick and HallsofIvy? Or did I scare them away :wink:
 
Last edited:

1. What is a very difficult integral?

A very difficult integral is a mathematical expression that involves complicated functions and cannot be easily evaluated using standard integration techniques.

2. How do you know if an integral is very difficult?

An integral is considered very difficult if it cannot be solved using common integration methods such as substitution, integration by parts, or partial fractions.

3. What are some strategies for solving a very difficult integral?

Some strategies for solving a very difficult integral include using advanced integration techniques such as trigonometric substitutions, numerical integration methods, or computer programs like Mathematica or Maple.

4. Can very difficult integrals have multiple solutions?

Yes, very difficult integrals can have multiple solutions. In some cases, the solutions may even involve complex numbers.

5. Are there real-world applications for very difficult integrals?

Yes, very difficult integrals have many real-world applications in fields such as physics, engineering, and economics. They are used to model and solve complex systems and problems.

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