An object starts at time t = 0 with a velocity of v0 = +50 m/s and undergoes a constant acceleration of a = -11 m/s^2.(adsbygoogle = window.adsbygoogle || []).push({});

b) How far from its starting (t = 0) position is the object at time t_1?

I get 44.5 meters. it sounds right 'cuz the equation would mean 0+50*1 - 11/2 *1^2 = 44.5 meters. But the computerized grading system still counts it as wrong. Am I making a stupid mistake or what?

thanks

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# Homework Help: Very easy mechanics problem - am i making a stupid mistake?

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