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Very simple capacitor problem.

  1. May 6, 2009 #1
    The capacitors in the circuit below are all identical. The EMF of the battery is unknown.
    http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys212/oldexams/exam1/sp08/fig24.gif [Broken]

    If the charge on the left-hand plate of C1 is +24 μC, what is the charge on the left-hand plate of C4?

    (a) Q4 = -24 μC
    (b) Q4 = -12 μC
    (c) Q4 = 0
    (d) Q4 = +12 μC
    (e) Q4 = +24 μC

    What's the concept behind this? Is it -24 uC because the left plate of C4 is next to the negative terminal of the battery?
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. May 7, 2009 #2

    rl.bhat

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    Homework Helper

    Only two left plates are connected directly to E. According to conservation of charges the charges on two plates must be equal and opposite.
     
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