- #1

- 78

- 0

## Homework Statement

3/x^2

when I take the quotient rule ,

I get:

(0*x^2-3*2x)/(x^2)^2

isn't that -6x/x^4 or -6/x^3

My calculator says -6 and so it is, but why and what am I missing?

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- Thread starter yoleven
- Start date

- #1

- 78

- 0

3/x^2

when I take the quotient rule ,

I get:

(0*x^2-3*2x)/(x^2)^2

isn't that -6x/x^4 or -6/x^3

My calculator says -6 and so it is, but why and what am I missing?

- #2

- 73

- 0

but at what point are you evalusting.did they give you a point or did you just type on your calculator.you have to have value of x.to type on your calculator

- #3

- 78

- 0

my answer was f'(t)=-1/sqrt(1-(3/t^2)^2)*-6t

f'(t)=6t/sqrt(1-9/t^4)

I got the "-6t" part wrong, it was supposed to be just -6.

when I differentiate just 3/x^2 into my calculator and it comes out -6

on my ti89 calc. I go to math, calculus, differentiate and type in:

d(3/x^2,x) and get -6

- #4

- 70

- 0

Instead of using the quotient rule, you might find it easier to evaluate

3 x^-2

3 x^-2

- #5

- 78

- 0

I should have looked into the mirror sooner, the problem was there all along!

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