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Very Simple Physics Problem

  1. Mar 6, 2006 #1
    i have just started physics in high school and i got this problem i want some help on this question:

    A small fish is dropped by a pelican that is rising steadily at 0.41m/s.
    a)After 1.8s, what is the velocity of the fish? Answer in units of m/s
    b)How far below the pelican is the fish after the 1.8s? Answer in units of m.

    if anyone can show me the steps and formulae, thanks.
     
  2. jcsd
  3. Mar 6, 2006 #2
    what steps have you taken so far? most people on this board like to see that you put some work in a problem before submitting it for help. Here is a hint:

    What effect does the fact that the pelican is rising have on the fall of the fish? Is gravity affected when you are moving against gravity at a gentle constant velocity?

    ~Lyuokdea
     
  4. Mar 7, 2006 #3
    vi= 0.41 m/s
    t-1.8s
    vf= ?
    a=9.8 m/s
    therefore u use vf=vi+at
    that is what i think i not quite sure for part a.
    for part b u use s=(vi+vf/2)*t or s=vit+1/2at^2
     
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