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VERY simple question about motion

  1. Feb 18, 2006 #1
    Okay, this is highschool physics I know but I still need to ask it.

    Say I give something a constant acceleration A straight up into the air (A = [0,0,+Az]). If I ignore drag, then the object's z-velocity as a function of time with this constant acceleration will be

    (Az - g)t

    (where Az is the z-component of the acceleration) if the initial z-velocity at time t = 0 is 0. Am I correct?

    Next question: say that an object is travelling straight up through the air with a constant velocity V0. Is the object's z-position as a function of time equal to

    V0t - 0.5gt^2 + Z0

    (where Z0 is the initial z position) or is it something else?

    Sorry if I didn't word these questions right - I'm still very new to this.
  2. jcsd
  3. Feb 18, 2006 #2
    If the object were traveling straight up at a constant velocity you wouldn't have the 0.5gt^2 term, this case would be equivilant to having Az=g in your previous example.
  4. Feb 18, 2006 #3


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