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Homework Help: Very simple question

  1. Feb 5, 2010 #1
    ok this is really easy. and i solved it once and now i can't get to the same solution.

    An object is moving in a straight line with a constant acceleration. Its position is measured at three different times, as shown in the table below.
    Time (s) | Position, (m)
    37.40 | 9.600
    38.60 | 15.804
    39.80 | 27.696
    Calculate the magnitude of the acceleration at t=38.60 s.

    so i tried with the x and v formuals, it gets me nowhere
    also tried with finding inclines.

    can u give me an outline of how to do it?

    thanks
     
  2. jcsd
  3. Feb 5, 2010 #2
    you know that the object from time 37.4 till 38.6 (s) moved from 9.6 to 15.804(m) , can you get the velocity from these information then substitute in any of the kinematic equations( i.e x = vot + 0.5 at^2 ) ..
     
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