Very VERY simple question

1. Dec 9, 2004

SomeRandomGuy

compute the following:

log base 4 (64) + 15*log base 32 (2)

I can't remember how to solve something like this. Makes me feel like an idiot, but I figured it never hurts to ask.

2. Dec 9, 2004

Integral

Staff Emeritus
You need the basic definition of a log.

C = logB A iff BC = A

Apply that definition and it should be pretty easy.

3. Dec 9, 2004

dextercioby

To prove that for yourself,try to apply the following formula
$$\log_{a}b =\frac{\log_{c} b}{\log_{c} a}$$
twice.

Daniel.

PS.I assumed you're familiar with this one:
$$\log_{c} x^{y} = y\log_{c} x$$.

4. Dec 9, 2004

HallsofIvy

Staff Emeritus
Integral's way is much simpler than dextercioby's.

64= 43 so log4 64= ?

32= 25 so 2= 321/5. What is log32 2?

Last edited: Dec 10, 2004