Hi i need some help with a differential equations problem. The question is:-(adsbygoogle = window.adsbygoogle || []).push({});

(w/g)y(double prime) + ky(single prime)+cy=F(t)

w= the weight of the object attached to the spring

g=32

k= damping factor

c=spring constant

F(t)= the external force on the system.

A 64 pound weight is attached to the end of the spring. After reaching the equilibrium position the spring is stretched one foot beyond the equilibrium position. The weight is then released and as it is released it is struck a downward blow giving it an initial velocity of 2 ft/sec. Take the moment the weight is released and struck as time zero. At time zero a periodic external force given by F(t) = (1/2)cos(4t) pounds begins acting on the system. t is time in seconds. Consider the damping factor to be negligible, i.e., take k to be zero. The spring constant is 32. Find the function giving y, the position of the bottom of the weight as a function of time given in seconds.

if some one could help me with this problem i would really appreciate it.

Thanks

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# Homework Help: Vibrating spring

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