1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Vibrating String

  1. Apr 10, 2008 #1
    1. The problem statement, all variables and given/known data
    The kinetic energy of a segment of length [tex] \Delta x [/tex] and mass [tex] \Delta m [/tex] of a vibrating string is given by [tex] \Delta K = \frac{1}{2} \Delta m (\frac{\partial y}{\partial t})^2 = \frac{1}{2} \mu (\frac{\partial y}{\partial t})^2 \Delta x [/tex], where [tex] \mu = \frac{\Delta m}{\Delta x} [/tex].

    a. find the total kinetic energy of the nth mode of vibration of a string of length L fixed at both ends.

    b. Give the maximum kinetic energy of the string.

    c. What is the wave function when the kinetic energy has its maximum value?

    d. Show that the maximum kinetic energy in the nth mode is proportional to [tex] n^2 A_n^2 [/tex].

    2. Relevant equations
    Pretty much given.

    3. The attempt at a solution
    I have tried numerous times to get a start on this problem but I can't seem to figure it out. Neither can my older brother or other peers :frown:.
  2. jcsd
  3. Apr 10, 2008 #2
    Ok, I can't answer them all, but here's what I can answer:

    We might as well work with differentials
    [tex]\frac{dK}{dx}=\frac{1}{2} \mu (\frac{\partial y}{\partial t})^2[/tex]

    Ok, the next bit is hand-wavy. For a vibrating string

    [tex]y(x,t) = Asin(\omega_{0} (t - x/\nu ))[/tex]

    where omega is the angular frequency- you may have seen it in some slightly different but equivalent form.

    [tex]\frac{\partial y}{\partial t} = A\omega cos(\omega_{0} (t - x/\nu )) [/tex]

    At t=0:
    [tex]\frac{\partial y}{\partial t} = A\omega cos(\omega_{0} x/\nu ) [/tex]

    [tex]\frac{dK}{dx}=\frac{1}{2} \mu (\frac{\partial y}{\partial t})^2 = \frac{1}{2} \mu (A \omega_{0} )^2 cos^2(\omega_{0} x/\nu )[/tex]

    So, in one wavelength:

    [tex]\int_{0}^{\lambda } \frac{1}{2} (A\omega_{0} )^2 cos^2(\omega_{0} x/\nu )dx [/tex]

    You will see that the integral is equal to:

    [tex]\frac{1}{4} \lamda \mu (A\omega_{0} )^2 [/tex]

    [tex]\omega_{0}[/tex] is the angular frequency of the first normal mode, and the frequency of the nth normal mode is [tex]n\omega_{0}[/tex]. Some of the results follow directly from that.

    As a matter of interest- what book are you using?
    Last edited: Apr 10, 2008
  4. Apr 10, 2008 #3
    Physics for Scientists and Engineers vol.5 by Paul A. Tipler
  5. Apr 11, 2008 #4
    I think I understand now. Thanks for the help.
  6. Jul 23, 2011 #5
    ???? What is the smallest possible 'unit' that can be in all of this.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Vibrating String
  1. A vibrating string (Replies: 2)

  2. Vibrating String (Replies: 1)

  3. Vibrating string (Replies: 3)

  4. String Vibrations (Replies: 1)