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## Homework Statement

An air compressor of mass m1 = 150 kg is mounted on a spring of stiffness k1= 3000 N/m. The measured

displacement amplitude X1 = 0.0002 m at the operating speed of N = 1800 r/min. If an undamped isolation

system with mass m2=12 kg and a natural frequency w2 = 105 rad/s is fixed to the compressor, calculate the

changed displacement amplitude X1 for the overall system

## Homework Equations

As far as I understand this is the relevant equation: X1/delta_st=(1-(omega/omega2)^2)/((1+k2/k1-(omega/omega_1)^2)(1-(omega/omega_2)^2)-k2/k1)

## The Attempt at a Solution

As far as I understand its a vibration absorber problem.

omega=1800*(2π/60)=188,5rad/s

omega1=(k1/m1)^.5=4.47

k2=omega_2^2*m2=105^2*12=132300N/m

X1/delta_st=(1-(omega/omega2)^2)/((1+k2/k1-(omega/omega_1)^2)(1-(omega/omega_2)^2)-k2/k1)

X1/delta_st=-5,836x10^-4

delta_st=-0,342m

I don't think that's right :|