• Support PF! Buy your school textbooks, materials and every day products Here!

Vibration of rigid body

  • #1

Homework Statement



Rigid body with one spring.


Homework Equations


Torque equations ( M=I * "alpha")

The Attempt at a Solution


So I think I can solve this problem but there is only one thing I do not understand.

When I am writing my torque equation I would think that the weight of the bar and the cube would affect the torque
M = I * a + Mb * g *0.4 cos (theta) + Mw * g * 0.4 cos (theta) - k*0.4sin(theta) *0.4 cos(theta)
but apparently the equation should be
M = I*a -k*0.4sin(theta)*0.4cos(theta)

why does the mg of both the objects not affect the torque, whenever I try to include them the differential equation becomes unsolveable
 

Attachments

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,230
31
From the equilibrium position, your forces would be along the lines of kδ=mgcosθ (component of the weight)

So that when the mass is displaced again by some distance x, the spring force becomes k(x+δ). And the weight cancels out.
 
  • #3
Alright thanks for the answer. Think I understand this now :)
 

Related Threads on Vibration of rigid body

  • Last Post
Replies
0
Views
1K
  • Last Post
Replies
7
Views
3K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
561
  • Last Post
Replies
2
Views
3K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
3
Views
5K
  • Last Post
Replies
6
Views
5K
  • Last Post
Replies
5
Views
4K
Top