A 500-g block is released from rest and slides down a frictionless track that begins 2.00 m above the horizontal as shown in the figure. At the bottom of the track, where the surface is horizontal, the block strikes and sticks to a light spring with a constant of 20 N/m.find the maximum distance the spring is compressed.(adsbygoogle = window.adsbygoogle || []).push({});

I think that I use the formula mgh=1/2kx^2 is this right?

so when i use this i get (.500)(9.8)(2)=.5(20)(x^2)

and solving for x i get .99m is this right?

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