- #1
Soaring Crane
- 469
- 0
How far from equilibrium will a 45 g mass with amp. of .35 m for a spring (k = 21 N/m) undergoing simple harmonic motion have a speed that is half its maximum velocity?
a. .3 m
b. .45 m
c. .7 m
d. .92 m
e. 3.5 m
Choice B is wrong.
Use
v = v_max*sqrt[1 - (x^2/A^2 m)]
Do I use k or m at all?
(1/2)v_max = v_max*sqrt[1 - (x^2/A^2 m)]
Left with:
1/2 =sqrt[1 - (x^2/A^2 m)]
After plugging everything in and solving for x I get .303m (A.). Am I wrong?
a. .3 m
b. .45 m
c. .7 m
d. .92 m
e. 3.5 m
Choice B is wrong.
Use
v = v_max*sqrt[1 - (x^2/A^2 m)]
Do I use k or m at all?
(1/2)v_max = v_max*sqrt[1 - (x^2/A^2 m)]
Left with:
1/2 =sqrt[1 - (x^2/A^2 m)]
After plugging everything in and solving for x I get .303m (A.). Am I wrong?
Last edited: