How far from equilibrium will a 45 g mass with amp. of .35 m for a spring (k = 21 N/m) undergoing simple harmonic motion have a speed that is half its maximum velocity? a. .3 m b. .45 m c. .7 m d. .92 m e. 3.5 m Choice B is wrong. Use v = v_max*sqrt[1 - (x^2/A^2 m)] Do I use k or m at all??? (1/2)v_max = v_max*sqrt[1 - (x^2/A^2 m)] Left with: 1/2 =sqrt[1 - (x^2/A^2 m)] After plugging everything in and solving for x I get .303m (A.). Am I wrong?