# Vibratrions and waves

1. Apr 6, 2005

### SwAnK

hey, i just need someone to see if i did this right, and if not to show me what i did wrong.

The question is:
a wave is travelling at 3m/s and has an amplitude of 2cm. If the distance between 2 consecutive toughs is 60cm, find the period of vibration and the total distance a little float would move as it bobs up and down as the wave passes by for 5 seconds.

What i did is using the universal wave formula I got
0.6f=3, so f is 5Hz. So then T would e the reciprocal which i got to be 0.2m/s. Then for distance would you not just multiply 5 by 3 to get the distamce travelled to get a total distance of 15m?

2. Apr 6, 2005

### dextercioby

What's T...?T should be the period and is $0.2 s$...

As for the second part,yes,it would be 15m.

Daniel.

3. Apr 6, 2005

### SwAnK

yes, sorry i got that, so when it says peroid of vibration, it is just talking about T, the period?

4. Apr 6, 2005

Of course.

Daniel.

5. Apr 6, 2005

### SwAnK

alrite, kewl, thanx a lot dextercioby!