(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Viete relations problem

1. The problem statement, all variables and given/known data

Find all real numbers r for which there is at least one triple (x,y,z) of nonzero real numbers such that

[tex] x^2 y + yz^2 + z^2 x = xy^2 + yz^2 + zx^2 = rxyz[/tex]

2. Relevant equations

http://en.wikipedia.org/wiki/Viète's_formulas

3. The attempt at a solution

This is equivalent to finding the possible values of r+s+t = 1/r + 1/s + 1/t where r,s,t are real but I don't see how that leads to a solution.

Fix r and assume that x,y,z exist. Let f(t) = t^3 + at^2 + bt+c be the monic polynomial with

x,y,z as its zeros. By assumption c is not zero. Its not hard to show that ab = (3+2r)c and a^3 = x^3+ y^3+z^3 + (3+2r)c using Viete's relations. But I am not sure what to do with those or how to get any sort of condition on r.

Please just provide a hint.

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# Homework Help: Viete relations problem

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