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Vinegar concentraion

  1. Feb 24, 2017 #1
    1. The problem statement, all variables and given/known data
    After diluting 20.00mL of vinegar sample to 500.0 mL in a volumetric flask, a student titrated a 20.00 mL aliquot of this diluted solution against a 0.1120 M NaOH solution. The acetic acid requires 27.98 mL of base. What is the % HC2H3O2 in vinegar?

    2. Relevant equations
    M1V1 = M2V2

    3. The attempt at a solution
    I tried to find the concentration of vinegar when it is added to base. So M1(20.00mL) = (0.1120 M NaOH)(27.98 mL). But I have no idea how I am supposed to find the mass %. Do I have to apply the formula to get to the M before its dilution and then use the density of vinegar? (Even though the density is not mentioned in the problem?).
    Thanks
     
  2. jcsd
  3. Feb 25, 2017 #2

    Borek

    User Avatar

    Staff: Mentor

    You do know where this equation comes from (and when it will fail)?

    http://www.titrations.info/titration-calculation

    And yes, you should know the density of the initial solution. You may initially assume it is just that of a pure water (actually it is a bit higher, but not much).
     
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