# Violin Harmonics

## Homework Statement

a 32 cm violin string with linear mass density is .36 gm/m is placed near a loudspeaker that is fed by an audio oscillator of variable frequency. It is found that hte string is set into oscillations at frequencies 1320 Hz and 1760 Hz as the frequency of the audio oscillator is varied continuously over the range of 1000-1800 Hz. Which harmonic is the 1320 Hz for the violin?

## Homework Equations

L = (wavelength)/2
v = (frequency)*(wavelength)

## The Attempt at a Solution

I am attempting to find the "lowest frequency of oscillation". so f=v/(2*L). L is known, but v is not. I am trying to find the velocity of the string, but this is where I encounter a problem.

atyy

This just tells me what i already know. I don't know the tension in the string, and can't solve for the velocity, so I'm back to square one.

## Homework Statement

a 32 cm violin string with linear mass density is .36 gm/m is placed near a loudspeaker that is fed by an audio oscillator of variable frequency. It is found that hte string is set into oscillations at frequencies 1320 Hz and 1760 Hz as the frequency of the audio oscillator is varied continuously over the range of 1000-1800 Hz. Which harmonic is the 1320 Hz for the violin?

## Homework Equations

L = (wavelength)/2
v = (frequency)*(wavelength)

## The Attempt at a Solution

I am attempting to find the "lowest frequency of oscillation". so f=v/(2*L). L is known, but v is not. I am trying to find the velocity of the string, but this is where I encounter a problem.

Maybe i oculd just do 1760-1320=440 (is this the fundamental frequency?)

atyy
Maybe i oculd just do 1760-1320=440 (is this the fundamental frequency?)

Yes, that seems to work.

Maybe i oculd just do 1760-1320=440 (is this the fundamental frequency?)

Yes.1320 and 1760 must both be divisible by the fundamentat frequency and if 1320 is harmonic number n then 1760 must be harmonic number n+1.Now you can work it out.Also, many questions have red herrings(information you don't need)

Got it, thanks for the help.