- #1
CaneAA
- 13
- 0
I would appreciate some clarification on working with lenses and virtual objects (when the object distance do is negative).
I'm not sure what happens when the do is negative and you get a positive value for di. On which side of the lens does the image go?
Normally, for a lens, if di is positive, it is a "real image" and goes on the side of the lens opposite the object; and if di is negative, it is a "virtual image" and goes on the same side of the lens as the object. But what are the rules for when you start out with a virtual object?
Thanks!
I'm not sure what happens when the do is negative and you get a positive value for di. On which side of the lens does the image go?
Normally, for a lens, if di is positive, it is a "real image" and goes on the side of the lens opposite the object; and if di is negative, it is a "virtual image" and goes on the same side of the lens as the object. But what are the rules for when you start out with a virtual object?
Thanks!