# Virtual particles

1. Feb 19, 2005

### Sterj

[SOLVED] virtual particles

If there is createn a virtual pair (anti particle A and its particle B) in vacuum what are they doing in their life time? Is A always at the same position like B or how can they annihilate? And if they annihilate, what's with the energy (does it disappear)? Has the anti particle negativ energy?

I hope you can answer this questions

2. Feb 19, 2005

### masudr

No. Due to a manifestation of the canonical commutation relations, we have

$$\Delta E \Delta t \ge \frac{h}{4\pi}$$

which means that in an ever decreasing short amount of time, the uncertainty of the energy increases. If $\Delta t$ is small enough, then $\Delta E[/tex] can be big enough for there to be enough energy for a particle-antiparticle pair to be created. Of course, this means that those two particles have to annihilate with each other before [itex]\Delta t$ is over, or if an external source of energy is given to the vacuum to make up for the $\Delta E$, then the two created particles can live on. The two particles won't generally be in the same position during their lifetimes.

Last edited: Feb 20, 2005
3. Mar 2, 2005

### marlon

A virtual particle transfers a definite momentum p, so due to HUP it is everywhere.

No, another virtual pair is produced

Yes

i urge you to read my journal. I have written several entries on this topic. Check it out
https://www.physicsforums.com/journal.php?s=&action=view&journalid=13790&perpage=10&page=2

Look at the bottom of the page
regards
marlon

Last edited: Mar 2, 2005
4. Mar 4, 2005

### Sterj

"No, another virtual pair is produced"

That would mean, that the "same" energy is always there?

5. Mar 4, 2005

### marlon

Ofcourse, that is the vacuum energy. It is because this energy is non-zero that them vaccuum fluctuations and virtual particles exist in the first place

I am sure i have told this before...

marlon

6. Mar 5, 2005

### Sterj

But if the same energy is alway there, it takes the energy "sentense" in danger (E1=E2).