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Vmax of Block (SHM)

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  1. Jul 13, 2017 #1
    1. The problem statement, all variables and given/known data
    A block with mass m=200g is attached to a spring with a elastic constant of k=5.0 N/m.
    The block is pushed at a distance x=5.00cm of its equilibrium position, in a surface with no friction.
    Then its dropped of that position. Assume for t=0s that the block is at rest.
    What is the maximum velocity of the block? 3a1cb6fe8d8e320aa4a4bf6382213e13.png
    This is a multiple choice question, solutions being
    a) 0.250 m/s
    b) 1.25 m/s
    c) 0.05 m/s
    d) 5.0 m/s

    2. Relevant equations
    N/A

    3. The attempt at a solution
    bb927676ea389d454c9ec6b4ae65d102.png
    I can't figure how to find Vmax
     
  2. jcsd
  3. Jul 13, 2017 #2

    lightgrav

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    ok, that is Time Period and/or angular frequency ... do you want to use Hooke's Law (PE into KE), or do you want to use oscillation formulas?
     
  4. Jul 13, 2017 #3
    Oscillations I guess, I really can't figure out how to find Vmax. I've tried the Vmax=Aw but somehow it resulted in 1, which isn't the answer.

    Vmax = Aw = (0.2 kg)(5 rad/s) = 1.

    I'm really confused
     
  5. Jul 13, 2017 #4

    lightgrav

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    in oscillations, capital A is the oscillation Amplitude (not the mass)
    You need to keep track of your UNITS !
     
  6. Jul 13, 2017 #5
    Ok then so Vmax = Aw = (0.05)(5) = 0.250 m/s?

    It makes sense now.
     
  7. Jul 22, 2017 #6
    I think you can simply use the work energy theorem here.
     
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