- #1

- 14

- 0

The values range from 112 to -36dB. How can I properly interpret the attenuation loss in each case in this table? In other words, for a reference of 1 volt/meter and no signal loss, what is the expect value in dB?

- Thread starter Ionito
- Start date

- #1

- 14

- 0

The values range from 112 to -36dB. How can I properly interpret the attenuation loss in each case in this table? In other words, for a reference of 1 volt/meter and no signal loss, what is the expect value in dB?

- #2

- 4,662

- 5

dB = 20Log(V2/V1), or

V2/V1 = 10^

A change of a factor of two is

20Log(2) = 6.02 dB

Bob S

- #3

- 1,762

- 59

- #4

- 14

- 0

Hi skeptic2, completely sure about 1V/m, that is why I did not understand.

- #5

sophiecentaur

Science Advisor

Gold Member

2020 Award

- 25,475

- 5,002

If it is simply tabulating a mathematical relationship there need be no problem. If it it supposed to relate to some physical situation then it seems to have some rather high values: nearly 0.5 MV/m! Hardly a "signal" strength!

- #6

- 14

- 0

Therefore, the values I am seeing in the table correspond conversions of this reference. If the signal is not attenuated, I have 1V=1*10

- #7

sophiecentaur

Science Advisor

Gold Member

2020 Award

- 25,475

- 5,002

1V/m is 0dBV/m

or

1V/m is 120dBmuV/m

That's an identity, surely.

That assumes the same impedance. dB is actually a log of power ratio.

- Replies
- 15

- Views
- 1K

- Last Post

- Replies
- 3

- Views
- 1K

- Replies
- 2

- Views
- 7K

- Last Post

- Replies
- 2

- Views
- 2K

- Replies
- 4

- Views
- 330

- Last Post

- Replies
- 1

- Views
- 9K

- Last Post

- Replies
- 21

- Views
- 4K

- Last Post

- Replies
- 12

- Views
- 4K

- Last Post

- Replies
- 6

- Views
- 1K

- Replies
- 5

- Views
- 10K