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In a circuit includes R, L, C in series, we apply Faraday's law:

I*R + Q/C + 0 = - dψ/dt

Here VL = ∫E*dl across the inductor is zero. I know this because the inductor has no resistance and according to Omh's law VL = 0. But if we consider the formula VL = ∫E*dl how can you know that E = 0?

I mean that is there any way to explain the electric field between two ends of inductor is zero.

If so, E = 0 how electrons move from one end to the other end of inductor?