1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Voltage/Current Divider

  1. Sep 29, 2016 #1
    1. The problem statement, all variables and given/known data

    upload_2016-9-29_7-43-55.png
    2. Relevant equations
    • Vx=Vt(Rx/(Rx+Rt))
    • Ix=It(Rt/(Rt+Rx))
    3. The attempt at a solution
    • I first simplified the circuit to only one resistor to get the total It and got 0.0168 A.
    • I next made the split the circuit where there was a current Ia going through the 150 and 40 ohm resistors and a Ib going into the 75,60, and 30 ohm resistors.
    • I then used current division to get Ia and Ib.
    Now here is where the trouble is? I think I can easily get v2, but how do I get v1? I dont understand what resistor I should use to calculate it.

    Any help is much appreciated.
     
  2. jcsd
  3. Sep 29, 2016 #2

    gneill

    User Avatar

    Staff: Mentor

    ##v_1## is across both the 150 and 75 Ohm resistors. That is, they share the same potential difference. So how are those resistors connected to each other?

    You might also want to re-check your circuit simplification to find the total current. The value that you found doesn't look right to me. Share your work if you're unclear on any steps.
     
    Last edited: Sep 29, 2016
  4. Sep 29, 2016 #3
    Maybe look at this sentence. The current going through 150 ohm and 40 ohm isn't exactly same.
     
  5. Sep 29, 2016 #4
    Thanks for the responses. So, based on what was said, I tried it through a different approach
    • I simplified the circuit into one with 1 resistor with a Rtotal=135 ohms. I did this by saying that since the 150 and 75 ohm resistors have the same voltage, they are in parallel and combined them to make a 50 ohm resistor in series with the 40. This left me with two 90 ohm resistors in parallel that I combined and added the 90 ohm resistor near the voltage source. I found Itotal= 22.2 mA
    • Now, I used current division to get the current going through the 50 ohm(found from 150 and 75) and 40 ohm, which are now in series. Did the same with the 60 and 30 ohm resistors. However, when calculating the resistance for the rest of the circuit excluding Rx(lets say for the 60 and 30 in this case), would Rrest of circuit=(50+40)||(90)?
     
  6. Sep 30, 2016 #5
    I didn't understand this. Why do you need resistance for rest of circuit? Once you've found the currents in the branches using current divider rule, you can find voltage across them using ohm's law.

    The 50 and 40 ohm would be in parallel with 90 ohm on left, if there were another voltage source on right and you were using superposition theorem or if you were finding Thevenin's resistance seen from right side to left. But that's not needed here.

    On a side note you can also solve the problem without finding currents in branches. Maybe try that and see if your answers match.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Voltage/Current Divider
  1. Voltage divider (Replies: 11)

  2. Voltage Divider (Replies: 2)

Loading...