Hi there... I know that in an inductor, its voltage will lead the current by 90 degrees and for a capacitor it wil lag the current by 90 degrees. I have seen the mathematical derivation for this too , but I can't get my head around what is actually physically happening here.(adsbygoogle = window.adsbygoogle || []).push({});

Why is the reactance of a capacitor less at greater frequencies? Whats happening with relation to the charges on the plates etc.. please someone help me, what is 'physically going on', as the mathematical derivation simply isn't enough for my curiousity...

Thanks all :rofl:

Regards

Brendan ;)

**Physics Forums - The Fusion of Science and Community**

# Voltage-Current lead/lag

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Voltage-Current lead/lag

Loading...

**Physics Forums - The Fusion of Science and Community**