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## Homework Statement

Hi,

We have this cut. :

and in the image below, I10 is calculated by using current division :

## The Attempt at a Solution

I tried to find it using voltage division but the answer is wrong :

Vx(of the upper node) = 100 * [tex]\frac{j5}{4+j5}[/tex] = 60.98 + j48.78 V

=> I10 = [tex]\frac{Vx}{10 - j5}[/tex] = 2.93 + 6.34 = 6.98 [itex]\ 65.2[/itex]

which is wrong, WHY?

thanks