Say you take an open circuited loop (not connected back to itself) and measure its voltage relative to some external reference point. Then you start rotating this loop in a magnetic field. Depending on the power of your motor, the loop will continue to spin for a finite amount of time. After this, the voltage with respect to the external reference point is much greater than it was before we rotated it. My question is how this potential energy is stored in the conductive loop. The overall charge of the loop did not change. Were the electrons bumped up to higher energy levels? If so , how does that translate to the movement of charge (current) when the circuit is closed? Edit: Nvm, I realize where I am going wrong. When the coil is not rotating, there will be no induced emf. Although answering my own question has raised another one; does each nucleus of the conductor (copper for example) have the same number of electrons associated with its outer shell? Or can the density of electrons vary in the conductor?