One application of an RL circuit is the generation of time varying high-voltage from a low-voltage source as shown in the figure. 1257 ohms 14 ohms 2 H (switch) b a 12.6 V. Sorry, I couldn't get the picture, but heres a rough idea.. it's in a circuit. What is the current in the circuit a long time after the switch has been in position "a"? I got this part... it was 0.9 A Part 2 says: Now the switch is thrown quickly from "a" to "b". Compute the initial voltage across the inductor. I got this too.. it was 1143.9 V Part 3 says: How much time elapses before the voltage across the inductor drops to 13 V? Answer in units of ms. I used the equation [tex] I= I_0 e^ (-R/L)t [/tex] and then figured out that [tex] V= I_0 Re^(-R/L)t [/tex] so 13.0 V=(0.9)(1143.9)e^(1143.9t/2) solving for t gave me 7.64 ms which isnt' right.. can someone please help me?