- #1
Rafeng404
- 17
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Poster has been reminded to use the Homework Help Template when starting threads in the schoolwork forums
Hi lads,
Working through my HND course books and I have come across a formula that I cannot get to give me the same answer as the book. Nor can some of my engineering student friends.
Values are:
F=50
C=500^-6
Rl = 100
Vc=31.03
The formula is
=(1/(2FsCRl))*(Vc-(Vr/2))
Inputting the values to make it look clearer it becomes
= (1/5)*(41.03-(Vr/2))
Solve for Vr.
My attempt:
=0.2(41.03-(Vr/2))
=8.206 * 0.1Vr
Vr= 8.206/0.1
Vr = 82.06
Clearly we have missed something stupid here and transposed it wrong. I am a bit rusty but I have lent my maths bible to someone else.
The right answer according to the uni is 7.46.
Have I completely forgotten how to do maths?
Thanks in advance
Working through my HND course books and I have come across a formula that I cannot get to give me the same answer as the book. Nor can some of my engineering student friends.
Values are:
F=50
C=500^-6
Rl = 100
Vc=31.03
The formula is
=(1/(2FsCRl))*(Vc-(Vr/2))
Inputting the values to make it look clearer it becomes
= (1/5)*(41.03-(Vr/2))
Solve for Vr.
My attempt:
=0.2(41.03-(Vr/2))
=8.206 * 0.1Vr
Vr= 8.206/0.1
Vr = 82.06
Clearly we have missed something stupid here and transposed it wrong. I am a bit rusty but I have lent my maths bible to someone else.
The right answer according to the uni is 7.46.
Have I completely forgotten how to do maths?
Thanks in advance