Voltage to charge capacitor

In summary, to store 7.50 x 10^-5 C of charge on the plates of a 7.0 µF capacitor, the required voltage is given by the equation V = q/C, where q is the charge and C is the capacitance. It is important to work in one set of units and make any necessary conversions, as well as correctly use numeric prefixes like "micro" = 10^-6.
  • #1
rcmango
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Homework Statement



What voltage is required to store 7.50 x 10-5 C of charge on the plates of a 7.0 µF capacitor?

i believe the equation to be: q = CV

so V = q/C

i've tried plugging in the numbers to this equation and don't get the correct answer. is 7.0 uF need to be converted to a more compatible number?

thankyou.

Homework Equations





The Attempt at a Solution

 
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  • #2
Yes, you need to work in one set of units, making any conversions that are necessary, and you need to do the right things with numeric prefixes like "micro" = 10^-6.

Write out your equation again for us, this time including the units and prefix multiplications, and we'll see where you are.
 
  • #3


To calculate the voltage required to store a certain amount of charge on a capacitor, the formula V = q/C can be used, where V is the voltage, q is the charge, and C is the capacitance of the capacitor. In this case, the capacitance is given as 7.0 µF, which can be converted to 7.0 x 10^-6 F. Plugging in the values, we get V = (7.50 x 10^-5 C)/(7.0 x 10^-6 F) = 10.71 V. Therefore, the voltage required to store 7.50 x 10^-5 C of charge on a 7.0 µF capacitor is approximately 10.71 V. It is important to make sure the units are consistent when using the formula, so converting the units to a more compatible number may be necessary.
 

1. What is the relationship between voltage and charge in a capacitor?

The voltage across a capacitor is directly proportional to the charge stored on the capacitor. This means that as the voltage increases, the charge stored on the capacitor also increases, and vice versa.

2. How do I calculate the charge on a capacitor given the voltage?

The charge on a capacitor can be calculated by multiplying the capacitance (C) of the capacitor by the voltage (V) across it. The formula is Q = CV.

3. Can a capacitor be fully charged?

No, a capacitor can never be fully charged as there will always be some leakage of charge due to the finite resistance of the capacitor's materials. However, the capacitor can be charged to a point where the leakage is negligible and the charge can be considered constant.

4. What happens to the voltage and charge on a capacitor when it is connected to a battery?

When a capacitor is connected to a battery, the voltage across the capacitor will increase until it reaches the same voltage as the battery. The charge on the capacitor will also increase until it reaches the maximum amount of charge that the battery can supply.

5. How does the voltage to charge ratio affect the energy stored in a capacitor?

The energy stored in a capacitor is directly proportional to the square of the voltage across it. This means that increasing the voltage will result in a larger amount of energy stored in the capacitor. However, be aware that increasing the voltage beyond the capacitor's rated limit can cause damage to the capacitor and potentially lead to failure.

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