The voltmeter in the figure below reads 6.2 V. If the vs = 12 V and R1 = 560 Ω, R2 = 470 Ω,
R3 = 680 Ω, and R4 = 4.7 kΩ, is the voltmeter reading correct?
The Attempt at a Solution
So I thought the voltage in the voltmeter would equal the voltage across the 4.7kohm resistor
So 12V*4700/(4700+560+470+680)= 8.798 V
So my answer would be no.
Is this correct or am I doing it wrong?
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