- #1

disregardthat

Science Advisor

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h = any dimension of the figure, A(h) = area of the cross-sections perpendicular to h described as a function of the position along h

this will work for any figure (no matter if the prism is slanted or the cross-sections change shape).

Can anyone maybe explain this to me? I want to find out how to integrate any forumula for Area of an object into a formula for Volume of an object.

The formula is this: [tex]\int A(h) dh[/tex]

This sentence that I don't understand is this:

Thanks.

this will work for any figure (no matter if the prism is slanted or the cross-sections change shape).

Can anyone maybe explain this to me? I want to find out how to integrate any forumula for Area of an object into a formula for Volume of an object.

The formula is this: [tex]\int A(h) dh[/tex]

This sentence that I don't understand is this:

**area of the cross-sections perpendicular to h described as a function of the position along h**Thanks.

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