Find the volume of the solid obtained by rotating the region bounded by the curves: x = 2 sqrt(y), x = 0, y = 9; about the y-axis I have this graphed and everything so I'm not sure there's a need to worry about that. Setup (integrating with respect to y): Outer radius = x = 2 sqrt(y). Inner radius = x = 0. Bounded by y = 9 and 0. 9 ∫π[2 sqrt(y)]^2 dy 0 Which is equivalent to: _______9 (2πy^2)| = 36π _______0 However, my book says the answer is 162π. What am I doing wrong?